Difficulty: Easy
Correct Answer: specific gravity of liquid
Explanation:
Introduction:
Engineers frequently compare a liquid’s heaviness to that of water without carrying units. This comparison uses specific gravity, also called relative density, which simplifies quick estimates of buoyancy, manometer readings, and pump sizing.
Given Data / Assumptions:
Concept / Approach:
Specific gravity SG is defined as SG = gamma_liquid / gamma_water (at reference temperature). Because both numerators and denominators carry the same units, SG is dimensionless and independent of unit systems. For density-based definitions, SG = rho_liquid / rho_water, which is equivalent since gamma = rho * g.
Step-by-Step Solution:
Verification / Alternative check:
Example: If an oil has gamma = 7.85 kN/m^3 and water has about 9.81 kN/m^3, then SG = 7.85 / 9.81 ≈ 0.80, a dimensionless number that immediately indicates buoyancy behavior (it will float on water).
Why Other Options Are Wrong:
Density of liquid: A property with units (kg/m^3), not a ratio to water. Compressibility: Describes volume change with pressure. Surface tension: An interfacial property (N/m). Relative viscosity: Ratio of viscosities, not specific weights.
Common Pitfalls:
Mixing up specific gravity with specific weight; using different temperature references for the liquid and water; reporting SG with units (it must be unitless).
Final Answer:
specific gravity of liquid
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