Most Efficient Depth for Circular Channel – Condition for Maximum Discharge The discharge through an open channel of circular section is maximum when the flow depth is approximately 0.81 times the diameter of the circular channel (y ≈ 0.81 D).

Difficulty: Easy

Correct Answer: 0.81 times

Explanation:


Introduction:
For partially full circular conduits used as open channels, one can find a depth that maximizes discharge for a given slope and roughness. This “most efficient” depth is a standard design datum in sewer and stormwater engineering.


Given Data / Assumptions:

  • Steady, uniform open-channel flow in a circular section.
  • Friction laws such as Manning or Chezy apply.
  • Diameter D is fixed; depth y varies with the central angle of wetted segment.


Concept / Approach:

Discharge Q is proportional to A * R^(2/3) for a given slope and roughness (Manning’s equation), where area A and wetted perimeter P depend on the wetted central angle. Maximizing Q with respect to depth yields the condition y/D ≈ 0.81, a widely tabulated result.


Step-by-Step Solution:

Express A(θ) and P(θ) for a circular segment; compute R(θ) = A/P.Form Q(θ) ∝ A(θ) * R(θ)^(2/3) and differentiate with respect to θ.Set derivative to zero to find optimal θ and convert to y/D.Obtain y/D ≈ 0.81 as the maximizing ratio.


Verification / Alternative check:

Design charts for circular conduits show peak Q near y/D ≈ 0.8–0.82 for typical friction laws, validating the rule of thumb 0.81.


Why Other Options Are Wrong:

0.34 and 0.50 are too shallow and reduce area. 0.67 under-utilizes the section. 0.95 is near full, where increased perimeter outweighs area gain.


Common Pitfalls:

Confusing the depth for maximum velocity with that for maximum discharge; neglecting that the optimum is insensitive to the exact friction law but not identical to the full-flow condition.


Final Answer:

0.81 times

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