Difficulty: Easy
Correct Answer: (dQ/Q) = (5/2) * (dH/H)
Explanation:
Introduction:
Discharge over a triangular (V-notch) weir is very sensitive to the head reading. Quantifying this sensitivity helps set instrumentation accuracy and staff-gauge resolution for field measurements.
Given Data / Assumptions:
Concept / Approach:
For a V-notch, Q ∝ H^(5/2). Taking logarithms and differentiating gives dQ/Q = (5/2) * (dH/H) when Cd and geometric factors are treated as constants. Thus, a 1% error in head yields about a 2.5% error in discharge.
Step-by-Step Solution:
Verification / Alternative check:
Repeating the same steps for rectangular weirs (Q ∝ H^(3/2)) yields dQ/Q = (3/2) * dH/H, illustrating the stronger sensitivity of triangular notches.
Why Other Options Are Wrong:
3/2 corresponds to rectangular weirs. 1/2 and 2 underestimate the exponent effect. 5/3 is not derived from the H^(n) dependence of triangular notches.
Common Pitfalls:
Ignoring uncertainty in Cd or notch angle; applying this relation when approach velocity correction is significant, which slightly alters K but not the exponent.
Final Answer:
(dQ/Q) = (5/2) * (dH/H)
Discussion & Comments