Difficulty: Easy
Correct Answer: 150%
Explanation:
Introduction / Context:
Demand factors account for peaking behavior within a day or year. Designers adopt empirical multipliers to size transmission mains, service reservoirs, and pumps to cope with short-duration peak loads.
Given Data / Assumptions:
Concept / Approach:
A common rule-of-thumb is that maximum hourly consumption is about 1.5 times the average hourly consumption (150%). This recognizes diurnal peaks in morning/evening. More refined designs further consider 'maximum day' factors and 'peak hour on peak day' factors, but for many exam and planning contexts, 150% is the accepted figure.
Step-by-Step Solution:
Let q_avg,h be average hourly consumption.Assume peak-hour factor = 1.5 → q_max,h ≈ 1.5 * q_avg,h.Convert to percent: 150%.
Verification / Alternative check:
Empirical peaking factors in numerous manuals give similar magnitudes; when combined with storage, systems can satisfy peaks without oversizing all conveyance.
Why Other Options Are Wrong:
Common Pitfalls:
Using a single factor universally; always refine with local consumption patterns, metering data, and seasonal variations.
Final Answer:
150%
Discussion & Comments