Selectivity and bandwidth — does a lower quality factor (Q) produce a narrower bandwidth in a resonant circuit?

Difficulty: Easy

Correct Answer: False

Explanation:


Introduction / Context:
Quality factor Q and bandwidth are inversely related in linear resonant circuits. Designers rely on this relation to meet selectivity specifications in filters and tuned amplifiers.


Given Data / Assumptions:

  • Single, lightly loaded resonant network with center frequency f0.
  • Half-power bandwidth definition applies: BW = f2 − f1 where response is 3 dB down from the peak.


Concept / Approach:

The standard relation is Q = f0 / BW. Therefore BW = f0 / Q. As Q decreases, BW increases; as Q increases, BW decreases. Hence a lower Q gives a wider bandwidth, not a narrower one.


Step-by-Step Solution:

Start with Q = f0 / BW.Rearrange: BW = f0 / Q.Decrease Q → denominator smaller → BW increases.Therefore, the statement claiming narrower bandwidth for lower Q is false.


Verification / Alternative check:

Simulation or lab measurements of an RLC circuit show that increasing series resistance reduces Q and broadens the resonance curve, confirming the inverse relationship between Q and BW.


Why Other Options Are Wrong:

  • The inverse relation holds for both series and parallel resonant forms under linear conditions.
  • Zero resistance is unrealistic; however, practical resistance simply sets Q and hence BW by the same formula.
  • Frequency range does not change the mathematical relationship.


Common Pitfalls:

Confusing sharpness of the peak (selectivity) with gain. Lower Q flattens and widens the resonance, even if peak amplitude also changes due to loading.


Final Answer:

False

Discussion & Comments

No comments yet. Be the first to comment!
Join Discussion