Selectivity and bandwidth — does a lower quality factor (Q) produce a narrower bandwidth in a resonant circuit?
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ATrue
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BFalse
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CTrue only for parallel resonance
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DTrue only when resistance is zero
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ETrue at low frequencies but not at RF
Answer
Correct Answer: False
Explanation
Introduction / Context:Quality factor Q and bandwidth are inversely related in linear resonant circuits. Designers rely on this relation to meet selectivity specifications in filters and tuned amplifiers.
Given Data / Assumptions:
- Single, lightly loaded resonant network with center frequency f0.
- Half-power bandwidth definition applies: BW = f2 − f1 where response is 3 dB down from the peak.
Concept / Approach:
The standard relation is Q = f0 / BW. Therefore BW = f0 / Q. As Q decreases, BW increases; as Q increases, BW decreases. Hence a lower Q gives a wider bandwidth, not a narrower one.
Step-by-Step Solution:
Start with Q = f0 / BW.Rearrange: BW = f0 / Q.Decrease Q → denominator smaller → BW increases.Therefore, the statement claiming narrower bandwidth for lower Q is false.Verification / Alternative check:
Simulation or lab measurements of an RLC circuit show that increasing series resistance reduces Q and broadens the resonance curve, confirming the inverse relationship between Q and BW.
Why Other Options Are Wrong:
- The inverse relation holds for both series and parallel resonant forms under linear conditions.
- Zero resistance is unrealistic; however, practical resistance simply sets Q and hence BW by the same formula.
- Frequency range does not change the mathematical relationship.
Common Pitfalls:
Confusing sharpness of the peak (selectivity) with gain. Lower Q flattens and widens the resonance, even if peak amplitude also changes due to loading.
Final Answer:
False