Difficulty: Easy
Correct Answer: True
Explanation:
Introduction / Context:Resonance in a series RLC circuit is a cornerstone concept in AC analysis, filters, and tuned amplifiers. At resonance, reactive effects cancel, leaving purely resistive behavior that maximizes current for a given source voltage.
Given Data / Assumptions:
Concept / Approach:
In series RLC, the net reactance is Xnet = XL − XC. Resonance is defined by Xnet = 0, which requires XL = XC. Solving XL = XC yields f0 = 1 / (2 * pi * sqrt(L * C)). At f0, impedance is purely resistive (equal to R), current is in phase with voltage, and reactive power exchange between L and C is internal and equal.
Step-by-Step Solution:
Set XL = 2 * pi * f * L.Set XC = 1 / (2 * pi * f * C).At resonance: XL = XC ⇒ 2 * pi * f0 * L = 1 / (2 * pi * f0 * C).Solve for f0 to confirm the equality criterion.Verification / Alternative check:
Measure phase angle between source voltage and current. At resonance, phase angle is zero and the power factor is unity, confirming XL = XC and Xnet = 0.
Why Other Options Are Wrong:
Common Pitfalls:
Mixing series and parallel resonance definitions. In parallel resonance, the condition is different when expressed in terms of susceptances and involves R, but the equality XL = XC in magnitude still indicates reactive cancellation.
Final Answer:
True
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