Reactive voltage cancellation — at resonance, do the inductor and capacitor voltage drops (VL and VC) cancel each other?

Difficulty: Easy

Correct Answer: True

Explanation:


Introduction / Context:
At resonance, reactive effects in RLC circuits balance. The concept of reactive voltage cancellation explains why the net reactive component of impedance disappears at the resonant frequency.


Given Data / Assumptions:

  • Series RLC circuit under sinusoidal steady state (the explanation also extends to reactive power in parallel resonance).
  • Inductive and capacitive reactances are equal in magnitude at resonance.
  • Finite resistance is present, so current is finite.


Concept / Approach:

In a series RLC at resonance, XL = XC. The inductor drop is VL = I * XL, and the capacitor drop is VC = I * (−XC) in phasor form. These two phasors are equal in magnitude and 180 degrees apart, so their sum is zero. The source therefore only supplies the resistive drop across R.


Step-by-Step Solution:

Set XL = XC at resonance.Compute VL = I * jXL and VC = I * (−jXC).Since XL = XC, VL + VC = I * jXL + I * (−jXL) = 0.Thus, reactive voltages cancel and only the resistive component remains in the loop sum.


Verification / Alternative check:

Applying Kirchhoff’s Voltage Law around the loop at resonance yields V_source = V_R, with the vector sum of VL and VC equal to zero. Oscilloscope measurements with current sensing show opposing inductor and capacitor waveforms that cancel vectorially.


Why Other Options Are Wrong:

  • Cancellation does not require zero resistance; it requires equality of reactances.
  • It is not restricted to parallel RLC; in parallel circuits, reactive powers cancel at resonance as well.
  • Infinite Q is unnecessary; finite Q simply limits peak magnitudes.


Common Pitfalls:

Interpreting “cancel” as “each voltage is zero.” VL and VC can be large individually at high Q, yet their phasor sum is zero at resonance.


Final Answer:

True

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