Difficulty: Medium
Correct Answer: h_f = (32 * μ * v * l) / (w * d^2)
Explanation:
Introduction / Context:In the laminar regime (Re < 2000 for pipes), head loss varies linearly with flow rate and viscosity. The Hagen–Poiseuille relation can be expressed in head form using specific weight, yielding a simple proportionality to length and velocity, and inversely to the square of diameter.
Given Data / Assumptions:
Concept / Approach:Darcy–Weisbach with laminar friction factor f = 64/Re leads to h_f = f * (l/d) * (v^2 / (2g)). Using Re = ρ * v * d / μ and w = ρ * g, rearrangement yields h_f = 32 * μ * v * l / (w * d^2). This is equivalent to the classical Hagen–Poiseuille pressure-drop formula divided by w to convert to head.
Step-by-Step Solution:
Start: h_f = f * (l/d) * (v^2 / (2g)), with f = 64 / Re.Re = ρ * v * d / μ ⇒ f = 64 * μ / (ρ * v * d).Substitute and simplify: h_f = (64 * μ / (ρ * v * d)) * (l/d) * (v^2 / (2g)) = (32 * μ * v * l) / (ρ * g * d^2).Use w = ρ * g ⇒ h_f = (32 * μ * v * l) / (w * d^2).Verification / Alternative check:For water at 20°C (μ ≈ 1.0e−3 Pa·s), small d and long l give appreciable head loss, matching practical experience in microchannels and viscous liquids.
Why Other Options Are Wrong:
Common Pitfalls:Using turbulent formulas in laminar range; forgetting v is mean velocity; mixing pressure drop and head loss without dividing by w.
Final Answer:h_f = (32 * μ * v * l) / (w * d^2)
Discussion & Comments