A 15 m ladder rests against a window 9 m above the ground on one side of a street. Keeping the foot fixed, it is turned to the other side to reach a window 12 m high. Find the width of the street.

Difficulty: Easy

Correct Answer: 21 m

Explanation:


Introduction / Context:
This is a classic two right-triangles setup sharing the same ladder length and foot position. Horizontal reaches to each wall add to the street width.


Given Data / Assumptions:

  • Ladder length L = 15 m.
  • Heights: 9 m on one side, 12 m on the other.


Concept / Approach:
For each side, horizontal distance to the wall is the base of a right triangle with hypotenuse 15 and vertical leg equal to the window height. Sum the two bases to get the street width.


Step-by-Step Solution:

Side 1: x^2 + 9^2 = 15^2 ⇒ x = √(225 − 81) = √144 = 12 mSide 2: y^2 + 12^2 = 15^2 ⇒ y = √(225 − 144) = √81 = 9 mWidth = x + y = 12 + 9 = 21 m


Verification / Alternative check:
Both bases are positive and consistent with the Pythagorean theorem; the same hypotenuse is used in each orientation.


Why Other Options Are Wrong:
30 m or 31 m double-count or miscompute the square roots; 12 m is just one side’s base.


Common Pitfalls:
Using 9 + 12 under the square root; forgetting to add bases from both walls.


Final Answer:
21 m

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