Difficulty: Medium
Correct Answer: kL ∝ (Pm/V)^0.33
Explanation:
Introduction / Context:The liquid-side mass transfer coefficient (kL) reflects the rate at which dissolved species cross the liquid film surrounding bubbles or particles. In stirred, aerated tanks with aqueous media, kL is often correlated with turbulence intensity, which in turn scales with specific power input (Pm/V).
Given Data / Assumptions:
Concept / Approach:Classical surface-renewal and turbulence theories predict that film thickness decreases with increasing energy dissipation, giving a sublinear power-law dependence of kL on (Pm/V). Empirical studies commonly report an exponent near 0.33 in water-like liquids, while the overall kLa includes an additional dependence on gas flow that governs interfacial area (a).
Step-by-Step Solution:
Relate turbulence to film renewal frequency: higher (Pm/V) increases eddy activity and reduces film thickness.Adopt empirical power-law form: kL ∝ (Pm/V)^n.For aqueous systems, n ≈ 0.33 is widely observed.Therefore, select kL ∝ (Pm/V)^0.33.Verification / Alternative check:Log–log plots of measured kL against (Pm/V) yield slopes close to 1/3 in water and dilute broths; deviations occur at high viscosity or with non-Newtonian rheology.
Why Other Options Are Wrong:
Common Pitfalls:Confusing kL with kLa; the latter depends on both kL and interfacial area a, which also varies with gas flow rate and dispersion quality.
Final Answer:kL ∝ (Pm/V)^0.33
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