BJT current relationships: In normal forward-active operation, is the collector current approximately equal to the base current?

Difficulty: Easy

Correct Answer: Incorrect

Explanation:


Introduction / Context:
Understanding the relative magnitudes of base current (I_B) and collector current (I_C) is essential when biasing BJTs. In forward-active operation, the collector current is controlled by the base–emitter junction but is typically much larger than the base current, with the ratio defined by current gain β (also written h_FE).


Given Data / Assumptions:

  • Forward-active region (not cutoff or deep saturation).
  • β is significantly greater than 1 for a typical small-signal BJT.
  • Steady quiescent bias with small-signal excursions.


Concept / Approach:
By definition, β = I_C / I_B. For common BJTs, β may range from tens to hundreds depending on device and operating point. Therefore, I_C ≈ β * I_B, making I_C much larger than I_B. Saying they are “approximately equal” is incorrect except in contrived cases where β ≈ 1, which is not representative of normal BJT behavior. Design equations and bias networks always account for a small I_B compared with I_C (and with emitter current I_E ≈ I_C + I_B).


Step-by-Step Solution:

Recall β definition: β = I_C / I_B.Typical β ≫ 1 ⇒ I_C ≫ I_B.Hence, I_C is not approximately equal to I_B in normal operation.Conclusion: the statement is incorrect.


Verification / Alternative check:
Datasheets list h_FE values; bench measurements with a simple CE stage confirm that a milliamp of I_C requires only microamps of I_B for β ~ 100.


Why Other Options Are Wrong:
Deep saturation changes relationships but the prompt says “in a BJT” generally; using β = 1 is atypical; feedback does not force equality of I_B and I_C.


Common Pitfalls:
Confusing current gain with voltage gain; forgetting that I_E ≈ I_C + I_B is the only near-equality, not I_C ≈ I_B.


Final Answer:
Incorrect

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