Biasing with fixed base resistor: In a simple “base bias” BJT configuration (base resistor from supply), what kind of Q-point stability does this method provide against β and temperature variations?

Difficulty: Easy

Correct Answer: A very unstable Q point

Explanation:


Introduction / Context:
Bias networks set the quiescent operating point (Q point) of a transistor amplifier. The simplest scheme, “base bias,” uses a single resistor from the supply to the base. Although easy to implement, this approach makes the Q point highly sensitive to transistor β (h_FE) and temperature, which shift base–emitter voltage and currents. Understanding this instability motivates better biasing methods for reliable designs.


Given Data / Assumptions:

  • Base bias topology: supply → R_B → base; emitter at or near ground; collector resistor to supply.
  • Large variation of β among parts and with operating conditions.
  • Temperature dependence of V_BE and leakage currents.


Concept / Approach:
With base bias, I_B is approximately set by (V_CC − V_BE) / R_B. The collector current I_C ≈ β * I_B; thus any β change causes a proportional change in I_C. Moreover, V_BE typically decreases about 2 mV/°C, altering I_B and I_C with temperature. There is no negative feedback path to correct these shifts, so the collector voltage and operating region can drift into cutoff or saturation, distorting signals or compromising headroom.


Step-by-Step Solution:

Write I_B ≈ (V_CC − V_BE)/R_B.Compute I_C ≈ β * I_B ⇒ strong dependence on β.Recognize temperature lowers V_BE and raises I_C for a fixed R_B.Conclude: Q point is very unstable.


Verification / Alternative check:
Replacing base bias with a voltage-divider bias and emitter resistor introduces negative feedback: emitter degeneration stabilizes I_C against β and temperature changes, a standard fix in textbooks and practice.


Why Other Options Are Wrong:
“Very stable” is false for base bias; “no current gain” contradicts β action; “zero current” is not a biasing outcome; “perfect temperature compensation” requires specific networks, not a lone base resistor.


Common Pitfalls:
Designing with a single measured β and ignoring spread; omitting emitter resistors that provide necessary stabilization.


Final Answer:
A very unstable Q point

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