Difficulty: Easy
Correct Answer: A very unstable Q point
Explanation:
Introduction / Context:
Bias networks set the quiescent operating point (Q point) of a transistor amplifier. The simplest scheme, “base bias,” uses a single resistor from the supply to the base. Although easy to implement, this approach makes the Q point highly sensitive to transistor β (h_FE) and temperature, which shift base–emitter voltage and currents. Understanding this instability motivates better biasing methods for reliable designs.
Given Data / Assumptions:
Concept / Approach:
With base bias, I_B is approximately set by (V_CC − V_BE) / R_B. The collector current I_C ≈ β * I_B; thus any β change causes a proportional change in I_C. Moreover, V_BE typically decreases about 2 mV/°C, altering I_B and I_C with temperature. There is no negative feedback path to correct these shifts, so the collector voltage and operating region can drift into cutoff or saturation, distorting signals or compromising headroom.
Step-by-Step Solution:
Verification / Alternative check:
Replacing base bias with a voltage-divider bias and emitter resistor introduces negative feedback: emitter degeneration stabilizes I_C against β and temperature changes, a standard fix in textbooks and practice.
Why Other Options Are Wrong:
“Very stable” is false for base bias; “no current gain” contradicts β action; “zero current” is not a biasing outcome; “perfect temperature compensation” requires specific networks, not a lone base resistor.
Common Pitfalls:
Designing with a single measured β and ignoring spread; omitting emitter resistors that provide necessary stabilization.
Final Answer:
A very unstable Q point
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