Difficulty: Easy
Correct Answer: Incorrect — an inductor does not boost current
Explanation:
Introduction / Context:Understanding how inductors influence current is essential in power converters, filters, and transient analysis. Inductors store energy in a magnetic field and resist changes in current according to v = L * di/dt. They are not active devices and cannot amplify current on their own.
Given Data / Assumptions:
Concept / Approach:Inductors follow v = L * di/dt. To increase current, a positive voltage must be applied; the inductor then allows current to ramp at a rate di/dt = v/L. This is not “boosting” by the inductor; it is the source doing work while the inductor stores energy. In steady DC state after transients, an ideal inductor behaves like a short, passing whatever current the surrounding resistance allows, but it never amplifies current beyond what the source provides.
Step-by-Step Solution:
Note the governing relation: v = L * di/dt.Recognize that current rises only when source voltage is applied across the inductor.In steady state (DC), v ≈ 0 across an ideal inductor, so current is set by external resistance.Therefore, an inductor does not boost current; it shapes its rate of change.Verification / Alternative check:Examine a buck converter: although inductor current can exceed input current instantaneously due to energy transfer and duty-cycle control, the “boosting” action is from switching and storage, not from the inductor acting as an amplifier by itself.
Why Other Options Are Wrong:
Common Pitfalls:Equating “passes more current in steady state” with amplification; misunderstanding that only active circuitry can provide gain; ignoring that inductors resist sudden current changes.
Final Answer:Incorrect — an inductor does not boost current
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