Inductor quality factor (Q): For a practical inductor modeled as an ideal L in series with winding resistance R, the quality factor Q at a given frequency is the ratio of inductive reactance to resistance, Q = X_L / R. Decide whether this statement is correct.

Difficulty: Easy

Correct Answer: Correct

Explanation:


Introduction / Context:
Quality factor quantifies how reactive energy storage compares to resistive loss. For inductors using the common series R-L model, Q is a simple and widely used measure in filters, resonant tanks, and RF chokes.


Given Data / Assumptions:

  • Series model: L with series R (winding and equivalent losses).
  • Operating at a single frequency f (since X_L depends on f).
  • Inductive reactance X_L = 2 * pi * f * L.


Concept / Approach:
Define Q for a series inductor as Q = X_L / R. Larger Q means lower loss relative to reactance. At resonance in an RLC, higher Q leads to narrower bandwidth. This definition is frequency-dependent and is appropriate when resistance is small compared to reactance (high-Q devices).


Step-by-Step Solution:

Compute X_L = 2 * pi * f * L.Measure or estimate series resistance R.Form Q = X_L / R (dimensionless).Interpret: higher Q implies better energy storage vs loss.


Verification / Alternative check:
Compare two inductors at the same f and L but different R; the one with lower R has higher Q, behaving closer to an ideal inductor (sharper resonance, lower insertion loss).


Why Other Options Are Wrong:

  • Incorrect/DC only: At DC, X_L = 0, so Q is undefined/zero. The relation applies at AC.
  • Core material only: Core affects losses and L, but Q still uses X_L/R.


Common Pitfalls:
Confusing series and parallel Q definitions; forgetting frequency dependence; ignoring additional core-loss components that can be folded into an effective R for small-signal models.


Final Answer:
Correct

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