Difficulty: Easy
Correct Answer: It uses no ferromagnetic core; the coil surrounds air or a non-magnetic former.
Explanation:
Introduction / Context:
Cores determine an inductor’s inductance, quality factor, saturation behavior, and frequency performance. Designers must distinguish “air-core” from ferrite or powdered-iron cores to choose the right part for RF, power, or signal applications. This question clarifies what “air-core inductor” actually means.
Given Data / Assumptions:
Concept / Approach:
An air-core inductor has no ferromagnetic material (no ferrite, steel, or iron powder) within the coil. The “core” is literally air or a non-magnetic support like PTFE, ceramic, fiberglass, or plastic. Without a magnetic path of high permeability, inductance per turn is lower than with magnetic cores, but linearity is excellent and there is no magnetic saturation. Losses due to hysteresis are eliminated, making air-core designs ideal for high-frequency RF circuits and for applications requiring very high linearity or low distortion.
Step-by-Step Solution:
Verification / Alternative check:
Compare datasheets: air-core inductors show relatively low inductance for given size and turns, high self-resonant frequency, and minimal core losses; ferrite or powdered-iron cores show higher inductance density but may introduce saturation and frequency-dependent losses.
Why Other Options Are Wrong:
Common Pitfalls:
Assuming “air-core” refers to gaps in iron cores; it does not. Also, mistaking the plastic bobbin as a “core” with magnetic effects; non-magnetic formers contribute negligible permeability.
Final Answer:
It uses no ferromagnetic core; the coil surrounds air or a non-magnetic former.
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