Difficulty: Easy
Correct Answer: the inverted average of the individual inputs
Explanation:
Introduction:
Summing and averaging amplifiers are standard op-amp applications. By choosing resistor ratios appropriately, the same circuit can output a weighted sum, a true average, or a scaled/inverted version of either. This question checks if you can map the resistor relationship onto the mathematical function realized.
Given Data / Assumptions:
Concept / Approach:
For the inverting summer, Vout = −Rf * Σ (Vi / Rin). With Rf = Rin/N, this becomes Vout = −(1/N) * Σ Vi, which is the inverted average of the inputs. If a non-inverted average is desired, a second inverting stage (gain −1) can be added.
Step-by-Step Solution:
Start from KCL at virtual ground: Σ (Vi − 0)/Rin = (0 − Vout)/Rf.Rearrange: Vout = −Rf * Σ (Vi / Rin).Substitute Rf = Rin/N: Vout = −(Rin/N) * Σ (Vi / Rin) = −(1/N) * Σ Vi.Interpretation: output equals negative of the arithmetic mean of the inputs.
Verification / Alternative check:
Example with N = 4, inputs {1, 2, 3, 4} V gives Σ Vi = 10 V, average = 2.5 V. The circuit outputs −2.5 V, matching the formula. A unity-gain inverter afterward produces +2.5 V if a non-inverted average is required.
Why Other Options Are Wrong:
Common Pitfalls:
Final Answer:
the inverted average of the individual inputs
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