Astronomical surveying — altitude at lower culmination when a star passes the zenith A star has declination δ = 60° N. It culminates at the zenith for an observer (i.e., the upper transit is directly overhead). For the same observer, what is the altitude of the star at its lower culmination on the meridian?

Difficulty: Medium

Correct Answer: 30°

Explanation:


Introduction / Context:
This problem checks core celestial-sphere relations used in astronomical surveying. When a star crosses the local meridian it has two transits each sidereal day: the upper (higher) culmination and the lower (opposite) culmination. For circumpolar stars (those that never set), both culminations are above the horizon, and their altitudes are determined by simple formulas that involve the observer’s latitude and the star’s declination.


Given Data / Assumptions:

  • Declination of the star δ = +60° (north).
  • At upper culmination, the star is at the zenith → altitude h_upper = 90°.
  • Standard spherical astronomy relations for meridian transits are applicable.


Concept / Approach:
For an observer at latitude φ (north positive) and a star of declination δ (north positive), the meridian transit altitudes are:
Upper culmination (on the same side of the equator as the observer): h_upper = 90° − |φ − δ|.
Lower culmination (on the opposite side around the pole for a circumpolar star): h_lower = φ + δ − 90°.
If h_lower > 0°, the star is circumpolar for that observer. If h_lower ≤ 0°, the lower culmination occurs below the horizon.


Step-by-Step Solution:

From h_upper = 90° − |φ − δ| and h_upper = 90° (zenith), we get |φ − δ| = 0° → φ = δ = 60°.Compute the lower culmination altitude: h_lower = φ + δ − 90° = 60° + 60° − 90° = 30°.Therefore, the lower culmination is 30° above the horizon.


Verification / Alternative check:
Check circumpolar condition: a star is circumpolar if δ > 90° − φ. Here, 60° > 30°, so it is circumpolar. A positive h_lower (30°) is consistent with this condition.


Why Other Options Are Wrong:

  • 10° and 20°: underestimate the lower culmination altitude; they would imply a smaller φ + δ.
  • 40°: overestimates the lower culmination altitude for φ = δ = 60°.
  • 60°: would contradict the standard relation h_lower = φ + δ − 90°.


Common Pitfalls:
Using h_lower = 90° − φ − δ blindly (which gives −30° here) without recognizing that for circumpolar stars the proper expression is h_lower = φ + δ − 90°. Also, mixing sign conventions for declination and latitude can lead to errors.


Final Answer:
30°

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