In a beam, if the shear force at a given section is zero, what does this imply about the bending moment at that section?

Difficulty: Easy

Correct Answer: maximum

Explanation:


Introduction / Context:
Shear force V(x) and bending moment M(x) are linked by calculus. Identifying where V(x) = 0 helps locate extrema of M(x), which is critical for design because maximum moment controls required section modulus.



Given Data / Assumptions:

  • V(x) = dM/dx.
  • Beam is smooth and loading is well-behaved so derivatives exist.



Concept / Approach:
If V(x) = 0 at a section, then dM/dx = 0 there, meaning M(x) has a stationary value (extremum). In most practical beam problems, this stationary value corresponds to a maximum (occasionally a minimum or point of inflection depending on load distribution).



Step-by-Step Solution:
Start from dM/dx = V.Set V = 0 → dM/dx = 0 → M is extremal at that section.Under common downward loading, the stationary point between supports is typically the maximum positive bending moment.



Verification / Alternative check:
Second derivative test: d²M/dx² = dV/dx = -w(x). For downward w(x) > 0, the stationary point is a local maximum of M.



Why Other Options Are Wrong:

  • Zero: requires a specific boundary condition, not implied by V = 0.
  • Minimum or average: possible in special cases, but the standard implication in loaded spans is a maximum.



Common Pitfalls:

  • Forgetting the sign convention connecting w, V, and M.



Final Answer:
maximum

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