In a beam, if the shear force at a given section is zero, what does this imply about the bending moment at that section?
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Amaximum
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Bminimum
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Czero
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Daverage of maximum and minimum
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Enone of these
Answer
Correct Answer: maximum
Explanation
Introduction / Context:Shear force V(x) and bending moment M(x) are linked by calculus. Identifying where V(x) = 0 helps locate extrema of M(x), which is critical for design because maximum moment controls required section modulus.
Given Data / Assumptions:
- V(x) = dM/dx.
- Beam is smooth and loading is well-behaved so derivatives exist.
Concept / Approach:If V(x) = 0 at a section, then dM/dx = 0 there, meaning M(x) has a stationary value (extremum). In most practical beam problems, this stationary value corresponds to a maximum (occasionally a minimum or point of inflection depending on load distribution).
Step-by-Step Solution:Start from dM/dx = V.Set V = 0 → dM/dx = 0 → M is extremal at that section.Under common downward loading, the stationary point between supports is typically the maximum positive bending moment.
Verification / Alternative check:Second derivative test: d²M/dx² = dV/dx = -w(x). For downward w(x) > 0, the stationary point is a local maximum of M.
Why Other Options Are Wrong:
- Zero: requires a specific boundary condition, not implied by V = 0.
- Minimum or average: possible in special cases, but the standard implication in loaded spans is a maximum.
Common Pitfalls:
- Forgetting the sign convention connecting w, V, and M.
Final Answer:maximum