Traffic forecasting: If the present Average Daily Traffic (ADT) is 5000 vehicles and the annual growth rate is 10%, what is the average daily flow after 5 years (geometric growth)?

Civil Engineering Highway Engineering Difficulty: Easy
Choose an option
  • A
    6050 vehicles
  • B
    7050 vehicles
  • C
    8050 vehicles
  • D
    9050 vehicles
  • E

Answer

Correct Answer: 8050 vehicles

Explanation

Introduction / Context:Traffic forecasting is essential for capacity analysis and pavement design. When growth is compounded annually, future ADT is obtained using geometric progression. This quick computation feeds into design year volumes and equivalent axle load calculations.

Given Data / Assumptions:

  • Current ADT (A₀) = 5000 vehicles/day.
  • Annual growth rate g = 10% = 0.10.
  • Time horizon n = 5 years.
  • Use geometric growth (compounded annually).

Concept / Approach:

The geometric growth formula for average daily traffic after n years is Aₙ = A₀ * (1 + g)^n. Substitute the given values and compute to the nearest 10 vehicles (as in the options).

Step-by-Step Solution:

Aₙ = 5000 * (1 + 0.10)^5(1 + 0.10)^5 = 1.1^5 = 1.61051 (approx.)Aₙ ≈ 5000 * 1.61051 = 8052.55 vehicles/dayRounded to the nearest option → 8050 vehicles.

Verification / Alternative check:

Check successive compounding: Year 1: 5500; Year 2: 6050; Year 3: 6655; Year 4: 7321; Year 5: ≈ 8053. The result is consistent.

Why Other Options Are Wrong:

  • 6050, 7050, 9050: correspond roughly to years 2, between years 2–4, and above year 5 for 10% growth; they are not the 5-year value.

Common Pitfalls:

  • Applying linear growth instead of compound growth, which underestimates future volumes.
  • Rounding too early and getting 8000 instead of ≈8050.

Final Answer:

8050 vehicles.

Discussion & Comments
No comments yet. Be the first to comment!
Join Discussion