Astronomical refraction — first-order correction as a function of altitude If α is the observed altitude of a star, which expression approximates the refraction correction (in arcseconds) for standard conditions?

Difficulty: Easy

Correct Answer: 58″ * cot α

Explanation:


Introduction / Context:
Astronomical refraction bends light downward, making celestial objects appear higher than they truly are. A simple first-order formula provides a quick correction for moderate altitudes.


Given Data / Assumptions:

  • Standard pressure and temperature near sea level.
  • Moderate zenith distances (not very near the horizon).
  • Small-angle approximation using a first-order term.


Concept / Approach:

The classic first-order refraction formula uses the zenith distance z = 90° − α. Refraction R (arcseconds) ≈ 58″ * tan z. Substituting tan z = cot α gives R ≈ 58″ * cot α, which is easy to apply when altitude is known.


Step-by-Step Solution:

Start with R ≈ 58″ * tan z.Use z = 90° − α → tan z = cot α.Therefore R ≈ 58″ * cot α.


Verification / Alternative check:

More accurate models add higher-order terms (e.g., −0.066″ * tan^3 z). For typical field work at altitudes above about 15°, the first-order formula is sufficiently accurate.


Why Other Options Are Wrong:

  • (b) swaps tan z with tan α and is incorrect.
  • (c) and (d) have wrong functional form and units.
  • (e) has the right function of z but with the wrong coefficient.


Common Pitfalls:

  • Applying the first-order formula near the horizon where refraction becomes large and nonlinear.


Final Answer:

58″ * cot α.

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