Aquifer storage terms in groundwater hydrology:\r If n is porosity, y is specific yield, and r is specific retention of a soil or rock, which relationship is correct?
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An + y + r = 1
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Bn + y = r
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Cn + r = y
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Dy + r = n
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En + r + y = 0
Answer
Correct Answer: y + r = n
Explanation
Introduction / Context:Porosity and its partitions govern how much water an aquifer can store and release. Specific yield and specific retention split porosity into a drainable portion and a portion held by molecular and capillary forces. Recognizing their algebraic relationship is essential for well design and groundwater balance calculations.
Given Data / Assumptions:
- n is total porosity (void volume / total volume).
- y (specific yield) is the fraction of water that drains by gravity.
- r (specific retention) is the fraction retained against gravity.
Concept / Approach:By definition, total pore water divides into two mutually exclusive parts under gravity drainage: drainable (specific yield) and retained (specific retention). Therefore, their sum equals total porosity. This identity underlies volumetric water budget computations in unconfined aquifers.
Step-by-Step Solution:Start with total porosity n.Partition into y (drainable) and r (retained).Thus: y + r = n.
Verification / Alternative check:Laboratory drainage curves and field specific yield measurements confirm that the difference between porosity and specific retention equals specific yield for typical granular soils.
Why Other Options Are Wrong:
- Adding n to either side (e.g., n + y + r = 1) mixes dimensional fractions incorrectly.
- Equations setting n + y = r or n + r = y contradict the basic partition concept.
- n + r + y = 0 is non-physical since all are positive fractions.
Common Pitfalls:
- Assuming y equals n; fine-grained soils have large r, so y can be much smaller than n.
- Using porosity instead of specific yield in groundwater storage-change calculations, leading to large overestimates.
Final Answer:y + r = n