Difficulty: Easy
Correct Answer: cm/s
Explanation:
Introduction / Context:
The coefficient of permeability, also called hydraulic conductivity (symbol k), quantifies how readily water flows through a soil or porous medium under a hydraulic gradient. Choosing the correct unit is fundamental for interpreting laboratory tests (constant-head or falling-head) and for applying Darcy’s law in field problems such as seepage, dewatering, and design of filters and drains.
Given Data / Assumptions:
Concept / Approach:
Since q has the dimensions of velocity (volume flux per unit area), k must also have dimensions of velocity. Therefore, its unit must be a length per time. In common geotechnical practice (especially in older texts and many lab reports), centimetre–second units are used, so k is expressed in cm/s (alternatively m/s in SI). Units involving area per time (e.g., cm^2/s) are incorrect for k; those belong to diffusivity-type parameters, not to hydraulic conductivity.
Step-by-Step Solution:
Verification / Alternative check:
Laboratory constant-head test equations give k in terms like (Q * L) / (A * h * t), which reduce to length/time, confirming cm/s (or m/s) as correct.
Why Other Options Are Wrong:
Common Pitfalls:
Confusing hydraulic conductivity (L/T) with hydraulic diffusivity (L^2/T); mixing m/s and cm/s without unit conversion; reporting “permeability” as a dimensionless percentage.
Final Answer:
cm/s
Discussion & Comments