If $\log_{10} 5 + \log_{10} (5x + 1) = \log_{10} (x + 5) + 1$, then $x$ is equal to
Aptitude
Logarithm
Difficulty: Medium
Choose an option
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A1
-
B3
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C5
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D10
Answer
Correct Answer: 3
Explanation
### Concept & Formula
This equation requires condensing multiple logarithmic terms into a single term on both sides using the product rule. A key step is recognizing that an isolated integer must be converted into a logarithm before the equation can be resolved.
Product Rule:
$$ \log_a(M) + \log_a(N) = \log_a(M \cdot N) $$
Constant Conversion:
$$ 1 = \log_{10}(10) $$
### Step-by-Step Solution
**Given:**
$\log_{10}(5) + \log_{10}(5x + 1) = \log_{10}(x + 5) + 1$
**Step 1: Simplify the Left Side**
Apply the product rule to the left side, as both terms share base $10$:
$\log_{10}(5 \cdot (5x + 1))$
$\log_{10}(25x + 5)$
**Step 2: Simplify the Right Side**
To combine the terms on the right, we must express the integer $1$ as a base-$10$ logarithm. We know that $\log_{10}(10) = 1$.
Rewrite the right side:
$\log_{10}(x + 5) + \log_{10}(10)$
Now apply the product rule:
$\log_{10}(10 \cdot (x + 5))$
$\log_{10}(10x + 50)$
**Step 3: Equate the Arguments**
Our simplified equation is now:
$\log_{10}(25x + 5) = \log_{10}(10x + 50)$
Since the logarithmic bases on both sides are identical, their arguments must be equal:
$25x + 5 = 10x + 50$
**Step 4: Solve the Linear Equation**
Subtract $10x$ from both sides:
$15x + 5 = 50$
Subtract $5$ from both sides:
$15x = 45$
Divide by $15$:
$x = 3$
### Exam Strategy & Shortcut
Rather than solving the algebra, plug the options into the equation starting from the smallest integer.
Try $x = 3$:
Left Side: $\log(5) + \log(16) = \log(80)$
Right Side: $\log(8) + 1 = \log(8) + \log(10) = \log(80)$
The left and right sides match instantly. Option checking on linear log equations takes a fraction of the time compared to algebraic condensing.
### Common Pitfall
The most frequent mistake is ignoring the constant $1$ on the right side of the equation and incorrectly equating $(25x + 5)$ directly to $(x + 5)$. Remember that every single term must be incorporated into the logarithm before you can drop the "log" notation from both sides.
### Final Answer
**Therefore, the correct answer is 3.**