$\frac{1}{\log_a b} \times \frac{1}{\log_b c} \times \frac{1}{\log_c a}$ is equal to
Aptitude
Logarithm
Difficulty: Easy
Choose an option
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A$a + b + c$
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B$abc$
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C0
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D1
Answer
Correct Answer: 1
Explanation
### Concept & Formula
This problem requires two core properties of logarithms: the Reciprocal Rule (a derivation of the base-change formula) and the Chain Rule.
$$ \frac{1}{\log_x y} = \log_y x $$
$$ \log_x y \times \log_y z = \log_x z $$
### Step-by-Step Solution
* **Given:** A product of three reciprocal logarithms with varying bases.
$$ \frac{1}{\log_a b} \times \frac{1}{\log_b c} \times \frac{1}{\log_c a} $$
* **Calculation:** First, apply the reciprocal rule to move the logarithms from the denominator to the numerator. This swaps the base and the argument for each term.
$$ \log_b a \times \log_c b \times \log_a c $$
* Rearrange the terms to make the chain rule visually obvious. Place them so the argument of one log matches the base of the next.
$$ \log_c b \times \log_b a \times \log_a c $$
* Apply the logarithmic chain rule to the first two terms ($\log_c b \times \log_b a$). The $b$'s cancel out, collapsing the terms.
$$ \log_c a \times \log_a c $$
* Apply the chain rule again to the remaining terms. The $a$'s cancel out.
$$ \log_c c $$
* Apply the identity rule for logarithms, where a base to the power of 1 equals itself ($\log_x x = 1$).
$$ 1 $$
### Exam Strategy & Shortcut
An alternative and often faster visualization uses the standard Base Change Formula: $\log_x y = \frac{\log y}{\log x}$.
Applying this to the reciprocal format means $\frac{1}{\log_a b} = \frac{\log a}{\log b}$.
Transforming all three terms gives: $\frac{\log a}{\log b} \times \frac{\log b}{\log c} \times \frac{\log c}{\log a}$.
You can immediately see that every numerator perfectly cancels every denominator, leaving exactly 1.
### Common Pitfall
A major trap is confusing multiplication with addition. Students sometimes mistakenly try to convert the product of these fractions into the logarithm of a sum, which is mathematically impossible. Always rely on the base change formula when multiplying logarithms with different bases.
### Final Answer
**Therefore, the correct answer is 1.**