Traffic flow – theoretical maximum vehicles per hour from spacing and speed If vehicle length is L metres and the clear distance between successive vehicles is C metres, moving at a speed V km/h, the theoretical maximum flow N (vehicles per hour) is:
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AN = 1000 * V / (L + C)
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BN = 3600 * V / (L + C)
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CN = 3.6 * V / (L + C)
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DN = (L + C) / (1000 * V)
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EN = 3600 / (L + C)
Answer
Correct Answer: N = 1000 * V / (L + C)
Explanation
Introduction / Context:The simplest headway model treats vehicles as occupying a physical length L plus a clear spacing C. Converting this space headway to a time headway at speed V gives a quick estimate of the maximum possible flow rate.
Given Data / Assumptions:
- L = vehicle length (m).
- C = clear gap between vehicles (m).
- V = speed (km/h), assumed steady and uniform.
- Single lane, no lateral interference, ideal conditions.
Concept / Approach:Time headway t = distance headway / speed. Distance headway = L + C (m). Speed in m/s is V/3.6. Therefore t = (L + C) / (V/3.6). The flow N = 3600 / t.
Step-by-Step Solution:
Convert speed: V_kmh → V_ms = V / 3.6.Compute headway: t = (L + C) / V_ms = (L + C) / (V/3.6) = 3.6 * (L + C) / V.Compute flow: N = 3600 / t = 3600 / (3.6 * (L + C) / V) = 1000 * V / (L + C).Verification / Alternative check:Dimensional check: numerator 1000*V (m/h) divided by metres gives vehicles/h, consistent with units.
Why Other Options Are Wrong:Options B and E ignore the km→m conversion. Option C gives vehicles/s order. Option D is the reciprocal of the correct expression.
Common Pitfalls:Forgetting to convert km/h to m/s; misinterpreting C as time gap; overlooking acceleration/driver variability which reduce real-world capacity below this ideal value.
Final Answer:N = 1000 * V / (L + C)