Bulking of Sand – compute percentage bulking from height readings In a cylinder test, the depth of moist sand is 15 cm. After full inundation with water, the depth reduces to 12 cm. What is the percentage bulking of the moist sand?
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A10%
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B12%
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C15%
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D20%
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E25%
Answer
Correct Answer: 25%
Explanation
Introduction / Context:Bulking is the increase in apparent volume of sand due to a thin film of water around particles that causes them to repel and bridge. It is important for volumetric proportioning at site; failure to correct for bulking results in lean mixes and strength loss.
Given Data / Assumptions:
- Apparent depth (height) of moist sand in cylinder, hm = 15 cm.
- Depth after inundation (true volume with no bulking), hs = 12 cm.
- Same mass of sand before and after inundation; readings are proportional to volume.
Concept / Approach:Percentage bulking is computed with respect to the saturated (no bulking) condition as the base: Bulking % = [(Vm - Vs) / Vs] * 100 = [(hm - hs) / hs] * 100, since depth is proportional to volume in the same container.
Step-by-Step Solution:Compute difference in depths: hm - hs = 15 - 12 = 3 cm.Divide by saturated depth: 3 / 12 = 0.25.Convert to percent: 0.25 * 100 = 25%.Therefore, bulking of the moist sand = 25%.
Verification / Alternative check:Typical bulking curves show maxima around 20–35% at about 4–6% moisture content for fine sand, aligning well with the computed 25%.
Why Other Options Are Wrong:
- 10%, 12%, 15%, 20% are lower than the correct calculation based on the given measurements.
Common Pitfalls:Using moist volume directly for batching without bulking correction; always base volumetric batching on saturated-surface-dry or adjust volume by the measured bulking percentage.
Final Answer:25%