Highway/rail curves – long chord of a simple circular curve: For a simple circular curve of radius R and central (deflection) angle Δ, what is the expression for the length of the long chord joining the curve’s end points?

Introduction / Context:In highway and railway alignment, basic elements of circular curves—tangent length, long chord, mid-ordinate—are frequently needed. The long chord connects the points of tangency and depends on the curve radius R and the central angle Δ subtended at the curve center.

Given Data / Assumptions:

• Simple circular curve of radius R.
• Central (deflection) angle Δ in degrees or radians (consistent units).
• We seek the long chord length between curve end points.

Concept / Approach:The end points and the circle center form an isosceles triangle with vertex angle Δ at the center and equal sides of length R. The half-chord is opposite the half-angle Δ/2. Using elementary trigonometry, the half-chord equals R * sin(Δ/2), so the full chord is twice that value.

Step-by-Step Solution:

Verification / Alternative check:Check limits: as Δ → 0, sin(Δ/2) ≈ Δ/2 (in radians), so C ≈ R * Δ, which matches the arc approximation for small angles.

Why Other Options Are Wrong:

• R * cos(Δ/2), 2R * cos(Δ/2), R * sin(Δ/2) represent other curve elements (e.g., mid-ordinates or half-chords) but not the full long chord.

Common Pitfalls:Using degrees in calculators set to radians; confusing chord with arc length; forgetting the Δ/2 factor.

Final Answer:2R * sin(Δ/2)