Difficulty: Medium
Correct Answer: 5.73°
Explanation:
Introduction / Context:In metric practice, the degree of curve D is often defined as the central angle subtended by a standard chord length (commonly 30 m). This provides a convenient field measure linked directly to chords used during curve setting out by Rankine’s method.
Given Data / Assumptions:
Concept / Approach:Geometry gives the chord–angle relation: c = 2R * sin(D/2). Solving for D yields D = 2 * arcsin(c / (2R)). Substituting the given values produces the numeric degree of curve appropriate for field deflection-angle calculations.
Step-by-Step Solution:
Write formula: c = 2R * sin(D/2).Solve: D = 2 * arcsin(c / (2R)).Plug numbers: c / (2R) = 30 / (2 * 300) = 30 / 600 = 0.05.Compute: D = 2 * arcsin(0.05) ≈ 2 * 2.864789° ≈ 5.7296° ≈ 5.73°.Verification / Alternative check:Approximate small-angle check: arcsin x ≈ x (radians). Using radians: 0.05 rad ≈ 2.8648°, doubled gives ≈ 5.7296°, matching the exact computation.
Why Other Options Are Wrong:
Common Pitfalls:Using degrees in a calculator set to radians; confusing “degree of curve by arc length” with “degree by chord.”
Final Answer:5.73°
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