Metric degree of curve using a 30 m chord: For a simple circular curve with radius R = 300 m and the specified standard chord length c = 30 m, what is the degree of the curve (D)?

Difficulty: Medium

Correct Answer: 5.73°

Explanation:


Introduction / Context:
In metric practice, the degree of curve D is often defined as the central angle subtended by a standard chord length (commonly 30 m). This provides a convenient field measure linked directly to chords used during curve setting out by Rankine’s method.


Given Data / Assumptions:

  • Radius R = 300 m.
  • Standard chord c = 30 m.
  • D is the central angle subtended by chord c (in degrees).


Concept / Approach:
Geometry gives the chord–angle relation: c = 2R * sin(D/2). Solving for D yields D = 2 * arcsin(c / (2R)). Substituting the given values produces the numeric degree of curve appropriate for field deflection-angle calculations.


Step-by-Step Solution:

Write formula: c = 2R * sin(D/2).Solve: D = 2 * arcsin(c / (2R)).Plug numbers: c / (2R) = 30 / (2 * 300) = 30 / 600 = 0.05.Compute: D = 2 * arcsin(0.05) ≈ 2 * 2.864789° ≈ 5.7296° ≈ 5.73°.


Verification / Alternative check:
Approximate small-angle check: arcsin x ≈ x (radians). Using radians: 0.05 rad ≈ 2.8648°, doubled gives ≈ 5.7296°, matching the exact computation.


Why Other Options Are Wrong:

  • 5.37°, 3.75°, 3.57° are inconsistent with the chord–radius relation for c = 30 m and R = 300 m.


Common Pitfalls:
Using degrees in a calculator set to radians; confusing “degree of curve by arc length” with “degree by chord.”


Final Answer:
5.73°

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