Difficulty: Easy
Correct Answer: both decreases and becomes zero at critical pressure
Explanation:
Introduction / Context:
Understanding how latent heat of vaporisation varies with pressure is central to phase-equilibrium calculations, boiler and condenser design, and the thermodynamics of power cycles. As a liquid approaches its critical point, the distinction between liquid and vapour fades, and this is reflected directly in the behaviour of the heat of vaporisation.
Given Data / Assumptions:
Concept / Approach:
From the Clapeyron/Clausius–Clapeyron relation, latent heat λ is tied to the slope of the saturation curve and the specific volume change between vapour and liquid. With rising pressure (and temperature along the saturation line), the difference in specific volumes shrinks. Consequently, λ decreases and must vanish at the critical point where the two phases coalesce.
Step-by-Step Solution:
Verification / Alternative check:
Steam tables corroborate this trend: compare λ at 1 bar to values near the critical point of water (around 22.06 MPa). The latent heat diminishes steadily and becomes zero at the critical point.
Why Other Options Are Wrong:
Common Pitfalls:
Confusing heat of vaporisation with sensible heat; assuming constant latent heat across pressures; forgetting that phase boundaries vanish at the critical point.
Final Answer:
both decreases and becomes zero at critical pressure
Discussion & Comments