Difficulty: Easy
Correct Answer: 40
Explanation:
Introduction / Context:Elemental mass percent in a compound is a foundational concept for stoichiometry, analytical chemistry, and process formulation. Here we compute the percentage of oxygen in sodium hydroxide (NaOH).
Given Data / Assumptions:
Concept / Approach:Mass percent of an element = (mass of that element in one mole of the compound / molar mass of the compound) * 100%. For NaOH, we add atomic masses to get the formula mass, then compute the oxygen fraction.
Step-by-Step Solution:
M(NaOH) = 23 + 16 + 1 = 40 g/mol.Mass of oxygen per mole = 16 g.Percent oxygen = (16 / 40) * 100% = 40%.Verification / Alternative check:Check that the three mass percentages for Na, O, and H sum to 100%: Na = 23/40 = 57.5%; O = 40%; H = 2.5%; total = 100%.
Why Other Options Are Wrong:
Common Pitfalls:Using atomic percent instead of mass percent; mis-adding atomic masses; forgetting to multiply by 100.
Final Answer:40
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