Difficulty: Easy
Correct Answer: Normal (perpendicular) to both the current and the magnetic field
Explanation:
Introduction / Context:
The Hall effect is a foundational phenomenon in solid-state physics and electrical engineering. When an electric current flows through a conductor or semiconductor placed in a magnetic field, moving charge carriers experience a magnetic force that pushes them sideways, creating a measurable transverse voltage called the Hall voltage. Understanding the direction of the resulting internal electric field is essential for sensor design and for determining carrier type and mobility.
Given Data / Assumptions:
Concept / Approach:
The Lorentz force on a carrier of charge q moving with drift velocity v in magnetic field B is F = q (v × B). This force deflects carriers to one side, causing charge separation. The separation builds a transverse electric field EH that opposes further deflection. At equilibrium, q EH balances q (v × B), making EH perpendicular to both current (direction of v) and magnetic field B.
Step-by-Step Solution:
Verification / Alternative check:
Polarity of the Hall voltage reverses when carrier type changes (electrons vs. holes) or when B direction flips, but the orthogonality remains: the Hall field is always transverse to both current and magnetic field.
Why Other Options Are Wrong:
Along current (b) or parallel/anti-parallel to B (c, e) contradicts v × B geometry; “None” (d) ignores the well-established perpendicular Hall field.
Common Pitfalls:
Confusing the direction of EH with its polarity; forgetting that EH vanishes if either current or B is zero; overlooking that contact placement determines the measured Hall voltage sign.
Final Answer:
Normal (perpendicular) to both the current and the magnetic field
Discussion & Comments