Syllogism — Separate chains: bananas → guavas and apples/grapes overlaps Statements: • Some grapes are apples. • Some apples are bananas. • All bananas are guavas. • No guava is pomegranates. Conclusions: I) No grapes are pomegranates. II) Some guavas are grapes. III) Some guavas are apples. IV) No bananas are pomegranates. Choose the necessary conclusions.

Introduction / Context:
Two chains appear here: one establishing that bananas sit entirely inside guavas, and another that places some apples inside bananas. We must see what this forces about guavas and apples/bananas, while handling grapes and pomegranates cautiously.

Given Data / Assumptions:

• ∃x: x ∈ Grapes ∩ Apples.
• ∃y: y ∈ Apples ∩ Bananas.
• Bananas ⊆ Guavas.
• Guavas ∩ Pomegranates = ∅.

Concept / Approach:
From y ∈ Apples ∩ Bananas and Bananas ⊆ Guavas, the same y is a Guava and an Apple, proving “Some guavas are apples.” Since every Banana is a Guava and no Guava is a Pomegranate, it follows that no Banana is a Pomegranate. However, statements involving Grapes require the same Apple witness to be a Grape, which is not forced.

Step-by-Step Solution:

Verification / Alternative check:
Model where some apples are bananas (hence guavas), and independently some grapes are apples but not the banana apples. Then III and IV hold; I and II fail.

Why Other Options Are Wrong:
They include conclusions about grapes that depend on an overlap not enforced by the premises.

Common Pitfalls:
Assuming that two separate “some” statements over Apples refer to the same individuals.

Final Answer:
Both III & IV follow.