Statements: • Some papers are lamps. • Some lamps are bulbs. • Some bulbs are tubes. • Some tubes are walls. Conclusions: I. Some walls are lamps. II. Some bulbs are papers. III. Some tubes are lamps. IV. Some walls are papers. Choose the option that must follow.

Difficulty: Easy

Correct Answer: None follows

Explanation:


Introduction / Context:
This is a chain of four “some” statements. Without a universal inclusion to push a specific element across sets, no particular intersection among the endpoints is guaranteed.



Given Data / Assumptions:
Each line supplies existence of an overlap (papers∩lamps, lamps∩bulbs, bulbs∩tubes, tubes∩walls), but they may all refer to different elements.



Concept / Approach:
Conclusions I–IV assert overlaps between non-adjacent sets (e.g., walls with lamps or papers). These would only be necessary if the very same element served as the witness for multiple premises, which is not enforced.



Step-by-Step Solution:
• Try to reach I: we would need a lamp that is also a tube and a wall. Nothing forces this.• II: we would need a lamp that is a paper and also a bulb; again, not guaranteed.• III and IV similarly require multi-step identity of witnesses across independent “some” links.



Verification / Alternative check:
Model each premise with a different disjoint pair. All premises hold while I–IV are all false, proving that none follows necessarily.



Why Other Options Are Wrong:
They claim forced intersections that the premises do not secure.



Common Pitfalls:
Over-chaining “some” statements.



Final Answer:
None follows.

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