Difficulty: Easy
Correct Answer: Account for additional resistances to heat flow due to deposits and fouling
Explanation:
Introduction:
Over time, heat-exchanger surfaces accumulate deposits (scale, biofilm, particulates) that add thermal resistance and reduce performance. Engineers include a fouling factor to ensure that the exchanger meets duty even after fouling develops.
Given Data / Assumptions:
Concept / Approach:
Total overall resistance R_total = 1/U = (1/h_hot) + R_wall + (1/h_cold) + R_f,hot + R_f,cold. The fouling factors R_f,hot and R_f,cold account for expected deposit resistance, effectively lowering the allowable U for design and providing robustness against performance decay.
Step-by-Step Solution:
Start with clean U based on convection and conduction.Add fouling resistances R_f to obtain design U_d = 1 / (R_clean + R_f,total).Size area A using Q = U_d * A * ΔT_lm so duty is met despite fouling.
Verification / Alternative check:
Comparing clean and dirty performance during operation confirms that deposit buildup reduces U; fouling-factor allowances approximate this effect at design time.
Why Other Options Are Wrong:
Common Pitfalls:
Using overly conservative R_f values leading to excessively large exchangers; ignoring that fouling is asymmetric between hot and cold sides.
Final Answer:
Account for additional resistances to heat flow due to deposits and fouling
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