Thermal conductivity vs. porosity — As the porosity of a solid increases (more voids/air pockets within the solid matrix), how does the effective thermal conductivity of the solid change?

Difficulty: Easy

Correct Answer: decreases

Explanation:


Introduction:
Porosity is the volume fraction of voids inside a material. Most engineering solids conduct heat far better than still gases such as air. When porosity rises, more of the heat-flow path is replaced by low-conductivity gas or vacuum, so the bulk or effective thermal conductivity usually drops. This principle is widely used in thermal insulation (foams, aerogels, fibrous mats).


Given Data / Assumptions:

  • Solid matrix has higher intrinsic conductivity than the fluid in pores (commonly air).
  • Pores are static (no forced convection) and radiation is modest compared to conduction for typical temperatures and pore sizes.
  • Effective property refers to the homogenized behavior of the porous composite.


Concept / Approach:

Effective thermal conductivity keff of a two-phase composite (solid + gas) can be estimated with series/parallel bounds or mixing models (e.g., Maxwell–Eucken). Because kgas << ksolid in normal conditions, increasing porosity φ shifts keff toward the low-conductivity phase, thus reducing overall heat transport. Only at very high temperatures and large pores could radiation or natural convection inside pores complicate this trend, but in standard design ranges, keff decreases monotonically with φ.


Step-by-Step Solution:

Identify phases: solid matrix (high k) and pore fluid (low k).Recognize keff is a weighted response of both phases.As porosity φ increases, heat paths traverse more low-k regions → keff decreases.Conclude the correct qualitative trend: conductivity decreases with porosity.


Verification / Alternative check:

Empirical data for foamed polymers, refractory bricks, and sintered metals show declining keff with rising porosity. Analytical bounds (Hashin–Shtrikman) also predict lower keff as the volume fraction of the poorer conductor increases.


Why Other Options Are Wrong:

A: Increase contradicts the basic conduction contrast of solid vs. gas. C: Unchanged would require perfectly compensating mechanisms, atypical. D: While exotic cases exist (radiation-dominated), the general engineering answer is a decrease. E: No periodic oscillation with temperature occurs solely due to porosity.


Common Pitfalls:

Ignoring radiation/convection at extreme temperatures; for normal building and process temperatures, conduction dominates and the inverse relation holds.


Final Answer:

decreases

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