Series combination calculation: eight resistors each of 5.6 kΩ are connected in series in a DC circuit. What is the total equivalent resistance in ohms (Ω)?

Introduction / Context:
In basic circuit theory, resistors in series simply add. This question tests your ability to convert between kilo-ohms (kΩ) and ohms (Ω) and to compute the total resistance for a string of identical resistors connected end-to-end.

Given Data / Assumptions:

• Number of resistors in series: 8.
• Each resistor value: 5.6 kΩ.
• Ideal components; no temperature or tolerance effects considered.

Concept / Approach:

For series resistors, the equivalent resistance is the arithmetic sum: R_total = R1 + R2 + … + Rn. Unit consistency matters; convert kΩ to Ω if the answers are expressed in Ω. Recall 1 kΩ = 1,000 Ω.

Step-by-Step Solution:

Verification / Alternative check:

Sum directly in kΩ: 8 * 5.6 kΩ = 44.8 kΩ, which equals 44,800 Ω. Both routes agree exactly.

Why Other Options Are Wrong:

8 Ω confuses multiplication by count with unit scaling. 5,600 Ω is only one resistor. 4,480 Ω is off by a factor of 10 (missing the kilo-to-ohm conversion).

Common Pitfalls:

Forgetting to multiply by the number of resistors; mixing kΩ with Ω and dropping the 10^3 factor.

Final Answer:

44,800 Ω