Difficulty: Medium
Correct Answer: Rs. 560
Explanation:
Introduction / Context:There is a classic relation between simple interest (I) on a sum and the true discount (D) on the same sum for the same time and rate: the face value A equals (I * D) / (I − D). This follows from writing I and D in terms of A and r t and eliminating r t.
Given Data / Assumptions:I = ₹67.20, D = ₹60, same time and rate for both measures on the same sum.
Concept / Approach:Derivation outline: If I = A * x and D = A * x / (1 + x) with x = r t, then I − D = A * x^2 / (1 + x). Thus (I * D)/(I − D) = A.
Step-by-Step Solution:
A = (I * D) / (I − D) = (67.20 * 60) / (67.20 − 60) A = 4032 / 7.2 = ₹560Verification / Alternative check:Compute x from either I/A or D/(A − D): I/A = 67.20/560 = 0.12; D/(A − D) = 60/500 = 0.12. Consistent.
Why Other Options Are Wrong:They do not satisfy the identity A = (I * D)/(I − D) for the given I and D.
Common Pitfalls:Interpreting “discount” as banker’s discount; here “discount” is the true discount unless stated otherwise in this relation.
Final Answer:Rs. 560
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