Find the correctly matched pair: In each pair A–B, the second number should be the square root of the first number (i.e., B = sqrt(A)). Select the pair that satisfies this relation.

Difficulty: Easy

Correct Answer: 36 - 6

Explanation:


Introduction / Context:
This classification item asks you to recognize the correct functional mapping between two numbers in a pair. The mapping is B = sqrt(A). Exactly one option follows this rule; the rest are distractors.


Given Data / Assumptions:

  • Pairs to test: 42–4, 36–6, 32–2, 15–5.
  • All square roots considered are principal (non-negative) roots.


Concept / Approach:
If B = sqrt(A), then A must be a perfect square of B. Equivalently, A = B^2. We can check faster by squaring B and comparing to A.


Step-by-Step Solution:

Check 42–4: 4^2 = 16 ≠ 42 → not correct.Check 36–6: 6^2 = 36 = A → correct.Check 32–2: 2^2 = 4 ≠ 32 → not correct.Check 15–5: 5^2 = 25 ≠ 15 → not correct.


Verification / Alternative check:
Take sqrt(A) directly. sqrt(36) = 6 (integer). For 42, 32, and 15, the square roots are not integers matching the listed B values. Hence only 36–6 works.


Why Other Options Are Wrong:

42–4 fails because 42 is not 4^2.32–2 fails because 32 is not 2^2.15–5 fails because 15 is not 5^2.


Common Pitfalls:
Confusing square roots with other operations (like halving) or assuming near-perfect squares qualify. Only exact perfect squares satisfy the relation.


Final Answer:
36 - 6 is the only correctly matched pair.

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