TCA cycle yield — The NADH and FADH2 produced by oxidation of one acetyl-CoA in the citric acid cycle generate approximately how many ATP (classical P/O), not counting the substrate-level GTP?
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A3 ATPs
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B6 ATPs
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C11 ATPs
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D15 ATPs
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E8 ATPs
Answer
Correct Answer: 11 ATPs
Explanation
Introduction:ATP yield calculations often distinguish between ATP produced by oxidative phosphorylation from reduced cofactors and ATP (or GTP) produced directly by substrate-level phosphorylation. This question focuses only on ATP generated from the reduced cofactors derived from one acetyl-CoA in the TCA cycle, using classical P/O ratios.
Given Data / Assumptions:
- Per acetyl-CoA in TCA: 3 NADH and 1 FADH2 are produced.
- Classical assumptions: NADH → 3 ATP; FADH2 → 2 ATP.
- GTP (substrate-level) is excluded from the tally here.
Concept / Approach:Multiply the number of each reduced cofactor by its classical ATP yield and sum. Modern bioenergetics often uses ≈ 2.5 ATP per NADH and ≈ 1.5 ATP per FADH2, but many exam contexts retain the classical values for simplicity and historical continuity.
Step-by-Step Solution:
1) NADH contribution: 3 NADH * 3 ATP/NADH = 9 ATP.2) FADH2 contribution: 1 FADH2 * 2 ATP/FADH2 = 2 ATP.3) Sum from cofactors: 9 + 2 = 11 ATP.4) Note: adding the substrate-level GTP would raise the total TCA yield per acetyl-CoA to 12 ATP in classical accounting.Verification / Alternative check:Electron transport chain stoichiometry in older texts gives these rounded values. With modern P/O estimates, the same calculation yields ≈ 10.5 ATP, but the classical expected answer remains 11 ATP.
Why Other Options Are Wrong:
- 3 or 6 ATP: underestimate by ignoring multiple NADH or FADH2 contributions.
- 15 ATP: exceeds the classical sum from cofactors alone.
- 8 ATP: still undercounts the three NADH contribution.
Common Pitfalls:Accidentally including the 1 GTP/ATP from succinyl-CoA synthetase, which the question explicitly excludes.
Final Answer:11 ATPs.