Difficulty: Easy
Correct Answer: AcetylCoA
Explanation:
Introduction:Glycolysis ends with pyruvate, but the TCA cycle begins with acetyl-CoA condensing with oxaloacetate to form citrate. This question examines your knowledge of the crucial linking reaction that enables aerobic oxidation of carbohydrate-derived carbon in mitochondria.
Given Data / Assumptions:
Concept / Approach:The pyruvate dehydrogenase (PDH) complex in the mitochondrial matrix converts pyruvate to acetyl-CoA by oxidative decarboxylation, producing NADH and CO2. The resulting acetyl-CoA enters the TCA cycle by combining with oxaloacetate to form citrate, enabling full oxidation to CO2 and maximum ATP yield via oxidative phosphorylation.
Step-by-Step Solution:
1) Transport: pyruvate crosses into the mitochondrial matrix via the pyruvate carrier.2) Conversion: PDH complex catalyzes pyruvate + CoA + NAD+ → acetyl-CoA + CO2 + NADH.3) Entry: acetyl-CoA + oxaloacetate → citrate (citrate synthase), launching a TCA cycle turn.4) Thus, the TCA cycle receives carbon as acetyl-CoA, not as free pyruvate.Verification / Alternative check:PDH deficiency or thiamine deficiency (cofactor for PDH) leads to lactic acidosis and impaired aerobic energy production, highlighting the indispensability of acetyl-CoA formation from pyruvate.
Why Other Options Are Wrong:
Common Pitfalls:Confusing pyruvate’s identity as the end product of glycolysis with the actual TCA entry molecule acetyl-CoA.
Final Answer:AcetylCoA.
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