Algebraic simplification (compound fraction): If a = p/(p + q) and b = q/(p − q), evaluate ab / (a + b) in simplest form.

Difficulty: Easy

Correct Answer: pq / (p^2 + q^2)

Explanation:


Introduction / Context:
This problem requires careful manipulation of rational expressions. By putting a and b over a common denominator, we can form a + b and ab explicitly and then simplify the compound fraction ab/(a + b). The key move is recognizing that identical factors cancel cleanly.


Given Data / Assumptions:

  • a = p/(p + q)
  • b = q/(p − q)
  • p ≠ ±q (to avoid zero denominators)


Concept / Approach:
Compute numerator and denominator separately: ab and a + b. Use the identity (p + q)(p − q) = p^2 − q^2 and simplify. The cancellation of (p^2 − q^2) between numerator and denominator will leave a compact expression in p and q.


Step-by-Step Solution:

ab = [p/(p + q)] * [q/(p − q)] = pq / (p^2 − q^2)a + b = p/(p + q) + q/(p − q) = [p(p − q) + q(p + q)] / (p^2 − q^2)Simplify numerator: p^2 − pq + qp + q^2 = p^2 + q^2Thus ab/(a + b) = [pq/(p^2 − q^2)] / [(p^2 + q^2)/(p^2 − q^2)] = pq/(p^2 + q^2)


Verification / Alternative check:
Test with concrete values (e.g., p = 3, q = 1) to ensure the simplified expression matches the numeric computation of ab/(a + b). It does.


Why Other Options Are Wrong:

  • Other options either invert the result or drop necessary terms, failing to account for the combination in the denominator.


Common Pitfalls:
Forgetting to combine like terms p(−q) + q(p) = 0 (they cancel), leaving p^2 + q^2. Also, do not try to add numerators without establishing the common denominator first.


Final Answer:
pq / (p^2 + q^2)

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