Mycobacteria on Lowenstein–Jensen medium — Which species produces eugonic (luxuriant) growth on L–J medium under standard conditions?
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AM bovis
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BMycobacterium tuberculosis
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CBoth (a) and (b)
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DNone of the above
Answer
Correct Answer: Mycobacterium tuberculosis
Explanation
Introduction / Context:Lowenstein–Jensen (L–J) medium is a classic egg-based medium used for culturing mycobacteria. Understanding which species grow luxuriantly (eugonic) versus poorly (dysgonic) aids in preliminary identification of members of the Mycobacterium tuberculosis complex.
Given Data / Assumptions:
- Eugonic growth = abundant, rapid colony development relative to other complex members.
- We compare M. tuberculosis to M. bovis under standard incubation.
- Other conditions (e.g., additives) are not considered unless routinely used.
Concept / Approach:Mycobacterium tuberculosis is eugonic on L–J medium, producing rough, buff, non-pigmented colonies. In contrast, M. bovis is generally dysgonic, showing sparse growth and sometimes requiring special supplementation. This growth difference, while not definitive alone, is a recognized laboratory clue during species differentiation within the M. tuberculosis complex.
Step-by-Step Solution:
Recall standard growth descriptors on L–J medium.Associate eugonic growth with M. tuberculosis; dysgonic with M. bovis.Select "Mycobacterium tuberculosis" as the species with eugonic growth.Verification / Alternative check:Biochemical tests (e.g., niacin accumulation positive in M. tuberculosis) and molecular assays confirm species identity beyond growth characteristics.
Why Other Options Are Wrong:
- M. bovis: typically dysgonic; not luxuriant on L–J medium.
- Both/None: contradict established growth patterns used in preliminary ID.
Common Pitfalls:Overinterpreting colony size alone without accounting for incubation time and inoculum size; always corroborate with further tests.
Final Answer:Mycobacterium tuberculosis