Phase angle trend: As the frequency of the applied AC voltage increases in a series RL circuit, how does the current–voltage phase angle (|θ|) change?
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Adecreases
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Bincreases
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Cdoes not change
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Dcannot be determined without values
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Ebecomes zero immediately
Answer
Correct Answer: increases
Explanation
Introduction / Context:The phase angle between source voltage and current in a series RL depends on the ratio XL/R. Understanding how this ratio shifts with frequency is crucial for filter design and transient response intuition.
Given Data / Assumptions:
- Series RL with fixed R and L.
- Frequency f increases.
- θ = arctan(XL / R) (current lags voltage by θ in inductive circuits).
Concept / Approach:Since XL = 2 * pi * f * L, increasing f increases XL while R is constant. Therefore, XL / R increases, and θ = arctan(XL / R) increases monotonically toward 90° as frequency becomes very large.
Step-by-Step Solution:
At low f: XL small ⇒ θ small (close to 0°, nearly resistive).As f increases: XL grows ⇒ θ increases.At very high f: XL ≫ R ⇒ θ approaches 90° (strongly inductive).Verification / Alternative check:Bode intuition: The RL corner frequency fc = R / (2 * pi * L) marks where θ ≈ 45°. Above fc, the circuit becomes increasingly inductive, confirming the trend of increasing |θ|.
Why Other Options Are Wrong:
- 'decreases' or 'does not change': Contradict the XL dependence on frequency.
- 'cannot be determined': The direction is determinable independent of specific values.
- 'becomes zero immediately': Zero angle happens only at DC (f → 0) for ideal RL.
Common Pitfalls:
- Confusing series and parallel behavior; in parallel RL, current components behave differently but θ of branch currents is defined separately.
Final Answer:increases