Difficulty: Easy
Correct Answer: nearly constant
Explanation:
Introduction / Context:
Inductive loads smooth current by storing energy. In controlled rectifiers, this affects ripple, commutation, and device stress.
Given Data / Assumptions:
Concept / Approach:
Large inductance resists rapid changes in current (di/dt small). Consequently, the load current becomes a slowly varying (low-ripple) waveform that, over each cycle, appears nearly flat (quasi-DC) rather than sinusoidal.
Step-by-Step Solution:
Apply controlled voltage pulses to an L-dominant load.Inductor stores and releases energy, smoothing current.Resultant current exhibits small ripple → nearly constant.
Verification / Alternative check:
Ripple magnitude ΔI ≈ (V_eff / L) * Δt; with large L, ΔI becomes small even over the conduction interval.
Why Other Options Are Wrong:
Sinusoidal/Rectangular: Do not reflect strong smoothing action of L.
Absolutely constant: Idealized; in practice some ripple remains.
Common Pitfalls:
Assuming current shape follows voltage; with large L, current changes slowly and is far flatter.
Final Answer:
nearly constant
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