Current in commutating elements of a series inverter In a classic series (resonant) inverter topology, how do the commutating elements (L and C) relate to load current?

Introduction / Context:
In a series inverter, the commutating components (inductor and capacitor) are placed in series with the load, forming a resonant path used for both output generation and thyristor commutation. Understanding current paths is essential for component current ratings and losses.

Given Data / Assumptions:

• Series inverter with L, C, and load all in series.
• Thyristor switching excites the series LC resonance.
• Sinusoidal current pulses shape output voltage across the load.

Concept / Approach:

Because L and C are in series with the load, the same current flows through all series elements at each instant. Therefore, commutating components must be rated for the full load current (including peak resonant current), not a fraction of it. This is a key difference from parallel-type commutated inverters, where commutation elements may not carry full load current continuously.

Step-by-Step Solution:

Verification / Alternative check:

Waveforms show identical current through L, C, and load; voltages redistribute but current is common.

Why Other Options Are Wrong:

Options suggesting partial current or no current contradict the series nature; “any of the above” is incorrect for the classical series inverter.

Common Pitfalls:

Confusing series with parallel commutation topologies.

Final Answer:

the commutating elements carry full load current