Approximate efficiency of a chopper (DC–DC converter) What is a typical overall efficiency figure for a practical chopper operating under normal conditions?

Difficulty: Easy

Correct Answer: 80% or more

Explanation:


Introduction / Context:
DC–DC choppers use high-frequency switching to minimize dissipation and achieve high efficiency. Understanding realistic efficiency helps with thermal design and power budgeting for drives and power supplies.


Given Data / Assumptions:

  • Modern switching devices with low conduction and switching losses.
  • Reasonable magnetics and minimal control losses.
  • No extreme low-load or poorly designed cases.


Concept / Approach:

Losses arise from conduction (I^2R or Vce(sat)·I), switching (overlap and device capacitances), gate drive, magnetics, and ripple. With proper design, these are a small fraction of output power, yielding high efficiency well above 80% and often 90–95% for medium to high power converters.


Step-by-Step Solution:

Estimate conduction loss fraction small with low Rds_on or low Vce(sat).Switching at suitably chosen frequency controls switching loss.Ancillary losses (gate drive, control) are minor at scale.


Verification / Alternative check:

Datasheets and application notes routinely report efficiencies exceeding 85–95% under nominal load.


Why Other Options Are Wrong:

  • 50%, 20%, 5% are characteristic of linear regulators or faulty designs, not switching choppers.


Common Pitfalls:

Ignoring cooling and layout; excessive switching frequency without need; operating deep in light-load where fixed overheads dominate can reduce efficiency but rarely to very low values.


Final Answer:

80% or more

More Questions from Power Electronics

Discussion & Comments

No comments yet. Be the first to comment!
Join Discussion