Chopper (DC–DC converter) efficiency Is a DC chopper generally considered a high-efficiency power conversion circuit compared to linear regulation?

Difficulty: Easy

Correct Answer: True

Explanation:


Introduction / Context:
Choppers (switch-mode DC–DC converters) use high-frequency switching to adjust average voltage and current with low dissipation, unlike linear regulators which burn off the voltage difference as heat.


Given Data / Assumptions:

  • Idealized high-efficiency switches (MOSFETs/IGBTs) with low conduction and switching losses.
  • Properly designed magnetics and filters.
  • Continuous conduction typical but not mandatory to assert general efficiency.


Concept / Approach:

Switching devices operate either fully on (low voltage drop) or fully off (very low current), minimizing instantaneous power dissipation. Energy transfer via inductors/capacitors allows power processing with small losses, resulting in typical efficiencies often above 90% in practical designs.


Step-by-Step Solution:

Compare to linear regulation: P_loss_linear ≈ (Vin − Vout) * Iout.In a chopper, average P_loss ≪ P_out when designed well; losses are mainly switching, conduction, and magnetics.Therefore, overall efficiency is high relative to linear methods.


Verification / Alternative check:

Industry benchmarks for buck/boost converters routinely show 88–97% efficiency ranges under optimal conditions.


Why Other Options Are Wrong:

Limiting high efficiency to only low current or only high input voltage is incorrect; efficiency depends on design, not solely on these variables.


Common Pitfalls:

Ignoring switching and gate-drive losses at extreme frequencies or neglecting inductor core losses which can reduce efficiency if poorly selected.


Final Answer:

True

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