Difficulty: Easy
Correct Answer: (Vrms^2 - Vdc^2)^0.5
Explanation:
Introduction / Context:
Rectifier outputs contain a DC component plus ripple (AC component). Quantifying ripple is essential for filter design and performance evaluation. RMS values add in a mean-square sense when components are orthogonal (DC vs AC).
Given Data / Assumptions:
Concept / Approach:
Because the DC component is constant and the AC component has zero average, the mean of the square of the sum equals the sum of the means of the squares: Vrms^2 = Vdc^2 + (Vac_rms)^2. Therefore, Vac_rms = sqrt(Vrms^2 − Vdc^2).
Step-by-Step Solution:
Verification / Alternative check:
Check limiting cases: If ripple is zero, Vrms = Vdc → Vac_rms = 0. If Vdc = 0 (pure AC), Vac_rms = Vrms, as expected.
Why Other Options Are Wrong:
Common Pitfalls:
Subtracting RMS magnitudes directly instead of subtracting power (square) quantities; forgetting that RMS is a quadratic metric.
Final Answer:
(Vrms^2 - Vdc^2)^0.5
Discussion & Comments