Difficulty: Easy
Correct Answer: both as series or shunt mounted switch
Explanation:
Introduction / Context:
PIN diodes are the workhorse devices for RF and microwave switching, attenuation, and phase control. Thanks to their intrinsic region, they behave like current-controlled resistors at high frequencies. Designers routinely place them either in series with the signal path or in shunt to ground to realize Single-Pole Single-Throw (SPST) and Single-Pole Double-Throw (SPDT) switches across a wide frequency range.
Given Data / Assumptions:
Concept / Approach:
Under forward bias, stored charge in the intrinsic region lowers the RF resistance, enabling low-loss conduction. Under reverse bias, depletion produces a high impedance with small junction capacitance, yielding isolation. In a series switch, the diode sits in the signal path; low R_pi means low insertion loss in the ON state. In a shunt switch, the diode connects the line to ground; low R_pi in the OFF path (for the main line) means the shunt leg is reverse-biased and presents high impedance, while the ON state of the shunt leg shorts RF to ground for isolation. Often, designers combine both series and shunt diodes to maximize isolation and minimize insertion loss.
Step-by-Step Solution:
Verification / Alternative check:
Typical datasheets specify insertion loss (ON) and isolation (OFF) for series, shunt, and series–shunt configurations, confirming all are valid placements for PIN switches.
Why Other Options Are Wrong:
Common Pitfalls:
Ignoring bias networks; forgetting that isolation depends on both diode resistance and residual junction capacitance; overlooking the benefit of adding a shunt path to a series-only design.
Final Answer:
both as series or shunt mounted switch
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