VSWR from power readings — directional coupler example In the setup shown (forward power meter at point A reads 1 mW; reflected power meter at point B reads 110 μW), determine the Voltage Standing Wave Ratio (VSWR) on the line.

Difficulty: Easy

Correct Answer: 2

Explanation:


Introduction / Context:
VSWR quantifies mismatch on a transmission line. Using a directional coupler or dual-direction power meter, one can read forward power P_f and reflected power P_r, convert to the magnitude of the reflection coefficient |Γ|, and then compute VSWR. This is a standard test-bench task in RF labs.


Given Data / Assumptions:

  • Forward power P_f = 1 mW at point A.
  • Reflected power P_r = 110 μW at point B.
  • Meters and coupler are properly calibrated; same reference impedance.


Concept / Approach:
The power reflection coefficient is |Γ|^2 = P_r / P_f. Hence |Γ| = sqrt(P_r / P_f). VSWR is defined as (1 + |Γ|) / (1 − |Γ|) for 0 ≤ |Γ| < 1. After computing |Γ| from the given readings, plug into the VSWR formula to get the final ratio.


Step-by-Step Solution:

Compute ratio: P_r / P_f = 110 μW / 1 mW = 0.11.Find |Γ|: |Γ| = sqrt(0.11) ≈ 0.3317.Compute VSWR: VSWR = (1 + 0.3317) / (1 − 0.3317) ≈ 1.3317 / 0.6683 ≈ 1.992.Round to nearest listed value: approximately 2.


Verification / Alternative check:
Convert |Γ| to return loss: RL = −20 * log10(|Γ|) ≈ 9.58 dB. The VSWR corresponding to about 9.6 dB return loss is ~2:1, which corroborates the calculation.


Why Other Options Are Wrong:

  • 1.5: corresponds to |Γ| ≈ 0.2, not 0.332.
  • 2.5: implies |Γ| ≈ 0.429, larger reflection than measured.
  • 3: implies |Γ| ≈ 0.5, much larger reflection.


Common Pitfalls:
Using power ratios directly in VSWR without taking the square root for |Γ|; mixing dB and linear units; misreading μW vs mW.


Final Answer:
2

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